/*
1.Write the sum of 1/(2^i) for i ranging from 0 to 2. 
2.Later generalise it to i ranging from 0 to N where N is a user defined input.  covered in task_5d code.
3.Challenge: Calculate 2^i without using pow function.
*/
#include <iostream>
//#include <math.h>
using namespace std;


/*to do task: write the function that computes s^exp*/
double user_function (double s, int exp) 
{
  double result ;
     
  return result ;
}

int main( )
{
 int         i =1 ;
 double      s= 0.5 ;// declaration

 for (i=0 ; i<=2 ; ++i)
     {
        
        s = s + user_function(s, i) ; // for task 3.
       //  s = s + pow (0.5s, ,i); // ( 0.0 + 0.5^0)  i=0, s=1
       //cout << " sum["<<i<<"] = " << user_function(s, i) << endl;
     }//for- loop



return 0;

}